1.

Iff(x)={1−|x|,|x|≤1|x|−1,|x|>1, and g(x)=f(x−1)+f(x+1). The value of 5∫−3g(x)dx

Answer» Iff(x)={1−|x|,|x|≤1|x|−1,|x|>1, and g(x)=f(x−1)+f(x+1). The value of 5∫−3g(x)dx


Discussion

No Comment Found