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Ifl_(1) = lim_(x to 2^(+)) (x + [x]) , l_(2) = lim_(x to 2^(-)) (2x - [x]) andl_(3) = lim_( x to pi//2)(cos x)/( x - pi//2) is |
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Answer» ` l_(1) LT l_(2) lt l_(3)` |
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