1.

Ifl_(1) = lim_(x to 2^(+)) (x + [x]) , l_(2) = lim_(x to 2^(-)) (2x - [x]) andl_(3) = lim_( x to pi//2)(cos x)/( x - pi//2) is

Answer»

` l_(1) LT l_(2) lt l_(3)`
`l_(2) , l_(3) , l_(1)`
`l_(3)lt l_(2)lt l_(2)`
`l_(1) , lt l_(3) lt l_(2)`

ANSWER :C


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