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Ifsinθsin2(π8+θ2)−sin2(π8−θ2)=k,θ≠2nπ, then value of 2k2 |
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Answer» Ifsinθsin2(π8+θ2)−sin2(π8−θ2)=k,θ≠2nπ, then value of 2k2 |
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