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Ifthe coinc ax^(2) + 2hxy + by^(2) + 2gx + 2fy + c = 0be a hyperbola , and the equation of the conjugate hyperbola is ax^(2) + 2hxy + by^(2) + 2gx + lambda = 0 , then lambda is equal to |
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Answer» `Delta/(AB - h^(2))` |
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