1.

(ii)A liquid of density rho and surface tension S rises to a height h in a capillary tube of diameter D. What is the weight of the liquid in the capillary tube? Angel of contact is 0^@.

Answer»

Solution :RISE of liquid in the capillary tube is given as,
`H=(2Scostheta)/(rho r g) `
Here, `r=(D)/(2). Theta=0^@., cos0^@=1`
So, `h=(2Sxx1)/(rhoxxD/2xxg)=(4S)/(rho DG)`
Now, weight of liquid in the capillary tube,
W = mass `xx` = m (volume `xx` DENSITY )`xx`g
`=(pir^2xxh)xxrhoxxg`
`=pi(D^2)/(4)xx((4S)/(rhoD g))xxrhoxxg=piDS`
This is the required result.


Discussion

No Comment Found