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(ii)A liquid of density rho and surface tension S rises to a height h in a capillary tube of diameter D. What is the weight of the liquid in the capillary tube? Angel of contact is 0^@. |
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Answer» Solution :RISE of liquid in the capillary tube is given as, `H=(2Scostheta)/(rho r g) ` Here, `r=(D)/(2). Theta=0^@., cos0^@=1` So, `h=(2Sxx1)/(rhoxxD/2xxg)=(4S)/(rho DG)` Now, weight of liquid in the capillary tube, W = mass `xx` = m (volume `xx` DENSITY )`xx`g `=(pir^2xxh)xxrhoxxg` `=pi(D^2)/(4)xx((4S)/(rhoD g))xxrhoxxg=piDS` This is the required result. |
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