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(ii) KMnO_(4)+Na_(2)SO_(3)to MnO_(2)+Na_(2)SO_(4)+KOH (Alkaline medium). |
Answer» Solution : Equalise the increase / decrease in O N by multiplaying Mn species by 2 and S species by 3 `2KMnO_(4)+3Na_(2)SO_(3)to 2MnO_(2)+3Na_(2)SO_(4)+KOH` Balance all other atoms except H and O `2KMnO_4 +3Na_(2)SO_3 to 2MnO_(2) +3Na_(2)SO_(4)+2KOH` Balance O atoms by adding `H_2O` molecules on the SIDE falling SHORT of oxygen atom . `2KMnO_(4)+3NaSO_(3)+H_(2)Oto 2MnO_(2)+3Na_(2)SO_(4)+2KOH` . |
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