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(ii) \( \lim _{x \rightarrow 1} \frac{\log x}{x-1} \) |
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Answer» \(\lim\limits_{x\to 1}\)\(\frac{log x}{x-1}\) (0/0 case) \(=\lim\limits_{x\to 1}=\frac{1/x}1\) (By using D.L.H. Rule) Hence, \(\lim\limits_{x\to 1}\)\(\frac{log x}{x-1}\) = 1 |
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