1.

(ii) \( \lim _{x \rightarrow 1} \frac{\log x}{x-1} \)

Answer»

\(\lim\limits_{x\to 1}\)\(\frac{log x}{x-1}\)   (0/0 case)

\(=\lim\limits_{x\to 1}=\frac{1/x}1\) (By using D.L.H. Rule)

Hence\(\lim\limits_{x\to 1}\)\(\frac{log x}{x-1}\) = 1



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