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II. \(\sqrt {129 + \sqrt {121}+ \sqrt {361}+ \sqrt {100} }= 13\)1). Only I2). Only II3). Neither I nor II4). Both I and II |
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Answer» Considering STATEMENT I, ⇒ √324 = 18 ⇒ √3.24 = √(324/100) = 18/10 = 1.8 ⇒ √0.0324 = √(324/10000) = 18/100 = 0.18 ⇒ √324 + √3.24 + √0.0324 = 18 + 1.8 + 0.18 = 19.98 Considering statement II, ⇒ √(129 + √121 + √361 + √100) = √(129 + 11 + 19 + 10) = √169 = 13 ∴ Both the statement are TRUE |
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