Imagine a light planet revolving around a very massive star in a circular orbit of radius .r. with a period of revolution T. On what power of .r. will the square of time period depend on the gravitational force of attraction between the planet and the star is proportional to r^(-5//2)

Imagine a light planet revolving around a very massive star in a circu

1.	Imagine a light planet revolving around a very massive star in a circular orbit of radius .r. with a period of revolution T. On what power of .r. will the square of time period depend on the gravitational force of attraction between the planet and the star is proportional to r^(-5//2)
Answer» Solution : The GRAVITATIONAL FORCE PROVIDES NECESSARY centripetal force `(mV^2)/R=K/r^(5//2) rArr V^2=K/(mr^(3/2))` So that `T=(2pir)/V=2pirsqrt((mr^(3//2))/K)` So `T^2 prop r^(7//2)`