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Imagine Earth to be a solid sphere. If the value of acceleration due to gravity at a depth 'd' below Earth's surface is the same as its value at a height 'h' above its surface and is equal to g/4then the ratio of h/dwill be ...... |
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Answer» 1 `:.g/4=g/(1+(h)/R)^2` `:. 4=(1+(h)/R)^2` `:. 2 = 1+h/R` `:.h/R =1 ""...(1)` `implies g(d) = g(1-d/R)^2` `:.g/4=g (1-d/R)` `:. 1/4 = 1 - d/R` `:. d/R = 1-1/4` `:. d/R =3/4 ""...(2)` `:. ` TAKING RATIO of equ . (1) and (2) `h/d =4/3` |
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