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In 1 L saturated solution of AgCl [K_(sp)(AgCl)=1.6xx10^(-10)], 0.1 " mol of " CuCl [ K_(sp)(CuCl)=1.0xx10^(-6)] is added. The resultant concentration of Ag^(+) in the solution is 1.6xx10^(-x). The value of "x" is |
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Answer» If `[Ag^(+)]=y "mol" L^(-1)` , then `K_(sp) (AgCl) = [Ag^(+)][Cl^(-)]` i.e., `1.6xx10^(-10) = y xx 10^(-3) or y = 1.6 xx 10^(-7)` . HENCE , x = 7 . |
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