1.

In 1 L saturated solution of AgCl [K_(sp)(AgCl)=1.6xx10^(-10)], 0.1 " mol of " CuCl [ K_(sp)(CuCl)=1.0xx10^(-6)] is added. The resultant concentration of Ag^(+) in the solution is 1.6xx10^(-x). The value of "x" is

Answer»


Solution :As `K_(sp)` of CuCl is much greater than that of AgCl, `Cl^(-)` ions PRESENT in the MIXTURE solution are mainly from CuCl and equal to `sqrt(10^(-6))`, i.e., `10^(-3) M`.
If `[Ag^(+)]=y "mol" L^(-1)` , then
`K_(sp) (AgCl) = [Ag^(+)][Cl^(-)]`
i.e., `1.6xx10^(-10) = y xx 10^(-3) or y = 1.6 xx 10^(-7)` . HENCE , x = 7 .


Discussion

No Comment Found