In 15 years, a principal lent becomes 9 times on Simple Interest. In h – InterviewSolution

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1.

In 15 years, a principal lent becomes 9 times on Simple Interest. In how many years will it be 33 times?1). 452). 603). 754). 90

Answer»

S.I = (P × R × T)/100

Where, P = principal

R = rate of interest

T = TIME in years

When T = 15, S.I = 9P – P = 8P

⇒ 8P = (P × R × 15)/100

⇒ R = 800/15 = 160/3

When P becomes 33 times that is 33P, S.I = 33P – P = 32P, T = ?

⇒ 32P = (P × 160/3 × T)/100

∴ T = 9600/160 = 60 years

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