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in 3 trials of binomial distribution, the probability of exactly 2 successes is 9 times the probability of 3 successes. find the probability of success in each trial. |
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Answer» Letprobabiltyofsuccesbep,henceaccordingtoquestion3C2p2(1−p)=9×3C3p3⇒3p2(1−p)=9p3⇒1−p=3p⇒4p=1⇒p=14 sdtvhf431-326+46742 |
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