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In `4 g` atoms of `Ag.` calculate a. Amount of `Ag.` b. Weight of one atom of `Ag`. (atoic weight of `Ag = 108`). |
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Answer» a. `4 g "atom" = 4 "mol of" Ag` `1 "mol of" Ag = 108 g` `4 "mol of" Ag = 108 xx 4 = 432 g` b. `1 "mol of" Ag = 6.023 xx 10^(23) "atoms"` `:. 6.023 xx 10^(23) "atoms" =? 108 g` `1 "atom" implies (1085)/(6.023 xx 10^(23)) g implies 17.93 xx 10^(-23) g` |
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