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In 6^(th) period if n = 6 and I = 0, 1, 2, 3, 4 there also why only 32 elements are there in this period ? |
Answer» Solution : Total 16 sub orbitals present so it CONTAIN 32 elements. Energy LEVEL ` = ns lt (n - 2) F lt (n - 1) d lt NP ` NOTE : `l = 4`, 3g orbital present it is not possible. |
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