1.

In 6^(th) period if n = 6 and I = 0, 1, 2, 3, 4 there also why only 32 elements are there in this period ?

Answer»

Solution :
Total 16 sub orbitals present so it CONTAIN 32 elements.
Energy LEVEL ` = ns lt (n - 2) F lt (n - 1) d lt NP `
NOTE : `l = 4`, 3g orbital present it is not possible.


Discussion

No Comment Found