In a 500 mL flask, the degree of dissociation of PCI_(5) at equilibrium is 40% and the initial amount is 5 moles. The value of equilibrium constant in mol L^(-1) for the decomposition of PCI_(5) is

In a 500 mL flask, the degree of dissociation of PCI_(5) at equilibriu

1.	In a 500 mL flask, the degree of dissociation of PCI_(5) at equilibrium is 40% and the initial amount is 5 moles. The value of equilibrium constant in mol L^(-1) for the decomposition of PCI_(5) is
Answer» 1.33 2.66 5.32 4.66 Solution : `K_(C)=([PCl_(3)](Cl_(2)])/([PCl_(5)])=(((2)/(0.5))((2)/(0.5)))/(((3)/(0.5)))=(8)/(30)=2.66`