In a 7.0 Levacuated chamber, 0.50 mol H_(2) and 0.50 mol I_(2) react at 427^(@) C. H_(2) (g) + I_(2) (g) hArr HI (g)+ Heat , At the given temperature, K_(c) = 49for the reaction.What is the total pressure (atm) in the chamber ?

In a 7.0 Levacuated chamber, 0.50 mol H_(2) and 0.50 mol I_(2) react a

1.	In a 7.0 Levacuated chamber, 0.50 mol H_(2) and 0.50 mol I_(2) react at 427^(@) C. H_(2) (g) + I_(2) (g) hArr HI (g)+ Heat , At the given temperature, K_(c) = 49for the reaction.What is the total pressure (atm) in the chamber ?
Answer» <P>83.14 831.4 8.21 None of these Solution :PV=nRT `IMPLIES p=(nRT)/(V)=(1 xx 0.0821 xx 700)/(7)=8.21` atm