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In a ∆ABC, AD is the bisector of ∠A. If AB = 10 cm, AC = 14 cm and BC – 6 cm, find BD and DC. |
Answer» If AB = 10 cm, AC = 14 cm and BC – 6 cm, find BD and DC. By angle-bisector theorem BD/DC = AB/AC = 10/14 Let BD = x cm and DC = (6-x) (As BC = 6 cm given) x/(6-x) = 10/14 14x = 10(6 – x) 14x = 60 – 10x 14x + 10x = 60 or x = 2.5 Or BD = 2.5 Then DC = 6 – 2.5 = 3.5 cm |
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