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In a ∆ABC, it is given that AD is the internal bisector of ∠A. If AB = 10cm, AC = 14cm and BC = 6cm, then CD = ? (a) 4.8cm (b) 3.5cm (c) 7cm (d) 10.5cm |
Answer» By using angle bisector in ∆ABC, we have AB/AC = BD/DC ⇒ 10/14 = 6 − x/x ⇒ 10x = 84 – 14x ⇒ 24x = 84 ⇒ x = 3.5 Hence, the correct answer is option (b). |
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