In a △ABC, let a,b and c denote the lengths of sides opposite to vertices A,B and C respectively. If a=7,b=3,c=5 andab(tanB2+tanC2)(tanA2+tanC2)+bc(tanA2+tanC2)(tanA2+tanB2)+ac(tanB2+tanC2)(tanA2+tanB2)equals k, then the value of √k+12 is

In a △ABC, let a,b and c denote the lengths of sides opposite to ver

1.	In a △ABC, let a,b and c denote the lengths of sides opposite to vertices A,B and C respectively. If a=7,b=3,c=5 andab(tanB2+tanC2)(tanA2+tanC2)+bc(tanA2+tanC2)(tanA2+tanB2)+ac(tanB2+tanC2)(tanA2+tanB2)equals k, then the value of √k+12 is
Answer» In a $△ A B C,$ let $a, b$ and $c$ denote the lengths of sides opposite to vertices $A, B$ and $C$ respectively. If $a = 7, b = 3, c = 5$ and $\frac{a b}{(tan \frac{B}{2} + tan \frac{C}{2}) (tan \frac{A}{2} + tan \frac{C}{2})} + \frac{b c}{(tan \frac{A}{2} + tan \frac{C}{2}) (tan \frac{A}{2} + tan \frac{B}{2})} + \frac{a c}{(tan \frac{B}{2} + tan \frac{C}{2}) (tan \frac{A}{2} + tan \frac{B}{2})}$ equals $k,$ then the value of $\sqrt{k} + \frac{1}{2}$ is