In `A^(+)B^(-)` ionic compound radii of `A^(=) and B^(-)` ions are `180 "pm "` and `187` pm respectively .The crystal structure of this compound will beA. NaCl typeB. CsCl typeC. ZnS typeD. similar to diamond

In `A^(+)B^(-)` ionic compound radii of `A^(=) and B^(-)` ions are `18

1.	In `A^(+)B^(-)` ionic compound radii of `A^(=) and B^(-)` ions are `180 "pm "` and `187` pm respectively .The crystal structure of this compound will beA. NaCl typeB. CsCl typeC. ZnS typeD. similar to diamond
Answer» Correct Answer - B `r_(+)//r_(-)=(180)/(187)=0.962` which lies in the range of `0.732-1.000`, hence co-ordination number = 8 i.e. the structure is CsCl type .

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In `A^(+)B^(-)` ionic compound radii of `A^(=) and B^(-)` ions are `180 "pm "` and `187` pm respectively .The crystal structure of this compound will beA. NaCl typeB. CsCl typeC. ZnS typeD. similar to diamond

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