In `A^(=)B^(-)` ionic compound radii of `A^(=) and B^(-)` ions are `180 pm ` and `187 pm` respectively .The crystal structure of this compound will beA. `NaCI` typeB. `CaCI` typeC. `ZnS` typeD. Similar to diamond

In `A^(=)B^(-)` ionic compound radii of `A^(=) and B^(-)` ions are `18

1.	In `A^(=)B^(-)` ionic compound radii of `A^(=) and B^(-)` ions are `180 pm ` and `187 pm` respectively .The crystal structure of this compound will beA. `NaCI` typeB. `CaCI` typeC. `ZnS` typeD. Similar to diamond
Answer» Correct Answer - b `r_(+) // r_(-) = (180)/(187) = 0.962 `which lies in the range of `0.732 - 1.000` hence coordination number `= 8 `i.e. the structure is `CaCI` type.

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In `A^(=)B^(-)` ionic compound radii of `A^(=) and B^(-)` ions are `180 pm ` and `187 pm` respectively .The crystal structure of this compound will beA. `NaCI` typeB. `CaCI` typeC. `ZnS` typeD. Similar to diamond

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