1.

In a bank, there are as many coins as the number of molecules in `1.6 mug` of `CH_(4)`. How many coins are there in the bank ?

Answer» Numbe of moles present `= ("Mass of methane")/("Molar mass of methane")`
`=((1.6xx10^(-6)g))/((16.0"g mol"^(-1)))=10^(-7) mol" "(1.0 mu g = 10^(-6) g)`
Number of molecules present `= (10^(-7))xx(6.022xx10^(23))=6.022xx10^(16)`
`:.` Number of coins in the bank `= 6.022 xx 10^(16)`.


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