1.

In a Binomial distribution with 5 trials the mean is 3. Find P and its variance.

Answer»

n = 5, Mean = np = 3 

Put n = 5 in np = 3; 5p 

= 3; p = \(\frac{3}{5}\) = 0.6; 

= 0.6; Var(X) = npq 

= 5 x 0.6(1 – 0.6) 

= 5 x 0. 6 x 0.4 = 1.2.



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