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In a Binomial distribution with 5 trials the mean is 3. Find P and its variance. |
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Answer» n = 5, Mean = np = 3 Put n = 5 in np = 3; 5p = 3; p = \(\frac{3}{5}\) = 0.6; P = 0.6; Var(X) = npq = 5 x 0.6(1 – 0.6) = 5 x 0. 6 x 0.4 = 1.2. |
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