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In a biprism experimentn the distancce virtua images of the slit is `2.5 mm` and the eypiece is a distance of 1 m from the slits. If the fringe width is `0.3` mm then the frequency of sources of lights isA. `4xx10^(14)Hz`B. `2xx1^(15)Hz`C. `4xx10^(12)Hz`D. `2xx1^(12)Hz` |
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Answer» Correct Answer - A `n=(V)/(lambda)=(v)/(d)(D)/(beta) " " ( :. lambda=d beta//D)` `=(3xx10^(8)xx1)/(2.5xx10^(-3) xx0.3xx10^(-3))=4xx10^(14)Hz` |
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