1.

In a bucket there are 5 purple, 15 grey and 25green balls. If the ball is picked up randomly, find the probability that it is neither grey nor purple?(a) \(\frac{5}{9}\)(b) \(\frac{12}{13}\)(c) \(\frac{51}{43}\)(d) \(\frac{2}{7}\)I had been asked this question in quiz.My question is based upon Geometric Probability topic in portion Discrete Probability of Discrete Mathematics

Answer»

The CORRECT answer is (a) \(\frac{5}{9}\)

To explain I would say: If the BALL is neither grey nor purple then it must be BLUE. There are 45 balls in TOTAL of which 25 are green and so the probability of picking a purple ball is \(\frac{25}{45} = \frac{5}{9}\).



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