In a cell reaction, `Cu_((s))+ 2Ag_((aq))^(+) to Cu_((aq))^(2+) + 2Ag_((s)) E_"cell"^@`=+0.46 V . If the concentration of `Cu^(2+)` ions is doubled then `E_"cell"^@` will beA. doubledB. halvedC. increased by four timesD. unchanged.

In a cell reaction, `Cu_((s))+ 2Ag_((aq))^(+) to Cu_((aq))^(2+) + 2Ag_

1.	In a cell reaction, `Cu_((s))+ 2Ag_((aq))^(+) to Cu_((aq))^(2+) + 2Ag_((s)) E_"cell"^@`=+0.46 V . If the concentration of `Cu^(2+)` ions is doubled then `E_"cell"^@` will beA. doubledB. halvedC. increased by four timesD. unchanged.
Answer» Correct Answer - D `E_"cell"^@=E_"cathode"^@-E_"anode"^@` It will remain unchanged

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In a cell reaction, `Cu_((s))+ 2Ag_((aq))^(+) to Cu_((aq))^(2+) + 2Ag_((s)) E_"cell"^@`=+0.46 V . If the concentration of `Cu^(2+)` ions is doubled then `E_"cell"^@` will beA. doubledB. halvedC. increased by four timesD. unchanged.

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