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In a certain region of space, there are only 5 molecules per cm^(3) on an average. The temperature is 3K. What is the average pressure of this very dilute gas ?"" (K = 1.38 xx 10^(-23)" J/mol K") |
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Answer» Solution :According to ideal gas equation PV = N KT where N is number of molecules (or) P = `(NKT)/(V) ` here `(N)/(V)` = 5 molecules /`cm^(3)` = 5 molecules / `(10^(-7)m)^(3)= 5 XX 10^(6)` molecules / `m^(3)` So P = `(5 xx 10^(6)) (1.38 xx 10^(-23))(3)` = `2.07 xx 10^(-16)` Pa |
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