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In a certain region of space there are only 5 molecules per cm^(3) on an average. The temperature is 3K. What is the average pressure of this very dilute gas ? (K=1.38 times 10^(-23)J//mol" "K) |
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Answer» <P> Solution :According to ideal GAS equation PV = `MU` RT.`P=(mu" "N_(A)kT//V)["as "R=N_(A)k]" (or) "P=(N//V)kT["as "mu" "N_(A)=N]" (or) "P=nkT" "["as "n=N//V]` here n = 5 molecules/`cm^(3)=5" molecules"//(10^(-2)m)^(3)=5 times 10^(6)"molecules"//m^(3)` So `P=(5 times 10^(6))(1.38 times 10^(-23))(3)=2.07 times 10^(-16)Pa` |
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