1.

In a chemical reaction `DeltaH` is 150 k J and `DeltaS` is `100 J K^(-1)` at 300 K, then `DeltaG` isA. 200 k JB. 333 k JC. 300 k JD. 120 k J

Answer» Correct Answer - D
`DeltaG=DeltaH-TDeltaS`
`=150-300(100xx10^(-3))=150-30=120 kJ`.


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