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In a city all telephone numbers have six digits. The first two digits are always 41 or 42 or 46 or 62. How many telephone numbers have all six distinct digits? |
Answer» If first two digit is 41, the remaining 4 digits can be arranged in `= ""^(8)P_(4) = (8"!")/(8 - 4"!") = (8"!")/(4"!")` `= (8 xx 7 xx 6 xx 5 xx 4"!")/(4"!")` ` = 8 xx 7 xx 6 xx 5 = 1680` Similarly, if first two digit is 42, 46, 62 or 64, the remaining 4 digits can be arranged in `""^(8)P_(4)` ways i.e., 1680 ways. `therefore` Total number of telephone numbers have all six digits distinct `= 5 xx 1680 = 8400` |
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