1.

In a class, 45% of the students drink orange and 90% of the remaining students drink Maaza No student drinks both Maaza and orange. Find the percentage of students in the class who drink neither Maaza nor orange.A. `4.5%`B. `6.5%`C. `7.5%`D. `5.5%`

Answer» Correct Answer - D
Let the strength of the class be 10%
The number of students who drink pulpy orange `=(45)/(100)(100x) =45x`
The number of students who dring Maaza`=(90)/(100) (100x -45x)`
`=(9)/(10)(55x) =49.5x`
No student drinks both Maaza and pulpy orange
The number of students of the class who drink neith Maaza nor pulpy orange `=10x -94 .5x =5.5x`
The required percentage `=(5.5x)/(100x) (100)% =5.5%`


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