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In a class, 45% of the students drink orange and 90% of the remaining students drink Maaza No student drinks both Maaza and orange. Find the percentage of students in the class who drink neither Maaza nor orange.A. `4.5%`B. `6.5%`C. `7.5%`D. `5.5%` |
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Answer» Correct Answer - D Let the strength of the class be 10% The number of students who drink pulpy orange `=(45)/(100)(100x) =45x` The number of students who dring Maaza`=(90)/(100) (100x -45x)` `=(9)/(10)(55x) =49.5x` No student drinks both Maaza and pulpy orange The number of students of the class who drink neith Maaza nor pulpy orange `=10x -94 .5x =5.5x` The required percentage `=(5.5x)/(100x) (100)% =5.5%` |
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