In A Class, There Are 15 Boys And 10 Girls. Three Students Are Select

1.	In A Class, There Are 15 Boys And 10 Girls. Three Students Are Selected At Random. The Probability That 1 Girl And 2 Boys Are Selected, Is?
Answer» LET's assume the sample space = S and Event of selecting 1 girl and 2 boys = E So, N(S) = Number ways of selecting 3 STUDENTS out of 25 = 25C3 => (25 * 24 * 23)/(3 * 2 * 1) = 2300. n(E) = (10C1* 15C2) = 10 * [(15 * 14)/(2 * 1)] = 1050. P(E) = n(E)/n(S) = 1050/2300 = 21/46. Let's assume the sample space = S and Event of selecting 1 girl and 2 boys = E So, n(S) = Number ways of selecting 3 students out of 25 = 25C3 => (25 * 24 * 23)/(3 * 2 * 1) = 2300. n(E) = (10C1* 15C2) = 10 * [(15 * 14)/(2 * 1)] = 1050. P(E) = n(E)/n(S) = 1050/2300 = 21/46.

In A Class, There Are 15 Boys And 10 Girls. Three Students Are Selected At Random. The Probability That 1 Girl And 2 Boys Are Selected, Is?

Answer»

LET's assume the sample space = S

and Event of selecting 1 girl and 2 boys = E

So, N(S) = Number ways of selecting 3 STUDENTS out of 25 = 25C3

=> (25 * 24 * 23)/(3 * 2 * 1) = 2300.

n(E) = (10C1* 15C2)

= 10 * [(15 * 14)/(2 * 1)] = 1050.

P(E) = n(E)/n(S) = 1050/2300 = 21/46.

Let's assume the sample space = S

and Event of selecting 1 girl and 2 boys = E

So, n(S) = Number ways of selecting 3 students out of 25 = 25C3

=> (25 * 24 * 23)/(3 * 2 * 1) = 2300.

n(E) = (10C1* 15C2)

= 10 * [(15 * 14)/(2 * 1)] = 1050.

P(E) = n(E)/n(S) = 1050/2300 = 21/46.