In a closed container at 1 atm pressure, 2 mole of SO_(2) (g) and 1 mole of O_(2)(g) were allowed to react to form SO_(3)(g) under the influence of a catalyst. The following reaction occurred: 2SO_(2)(g)+O_(2)(g) hArr 2SO_(3)(g) At equilibrium it was found that 50% of SO_(2)(g) was converted to SO_(3)(g). The partial pressure of O_(2)(g) at equilibrium will be :

In a closed container at 1 atm pressure, 2 mole of SO_(2) (g) and 1 mo

1.	In a closed container at 1 atm pressure, 2 mole of SO_(2) (g) and 1 mole of O_(2)(g) were allowed to react to form SO_(3)(g) under the influence of a catalyst. The following reaction occurred: 2SO_(2)(g)+O_(2)(g) hArr 2SO_(3)(g) At equilibrium it was found that 50% of SO_(2)(g) was converted to SO_(3)(g). The partial pressure of O_(2)(g) at equilibrium will be :
Answer» 0.66 atm 0.493 atm 0.33 atm 0.2 atm Answer :D