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In a coagulation experiment, `5mL` of `As_(2)S_(3)` is mixed with distilled water and `0.1M` solution of an electrolyte `AB` so that the total volume is `10mL` . It was found that all solutions sontianing more than `4.6mL` . Of `AB` coagulate within `5` min. What is the flocculation value of `AB` for `As_(2)S_(3)` solution? |
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Answer» A minimum of `4.6mL` of `AB` is required to coagulation the solution. The moles of `AB` in the sol is `=(4.6xx0.1)/(10)=0.046mol` This means that a minimum of `0.046mol` or `0.046xx1000=46` m mol are required coagulating `1L` of solution. Flocculation value of `AB` for `As_(2)S_(3)sol=46` A minimum of `4.6mL` of `AB` is required to coagulation the solution. The moles of `AB` in the sol is `=(4.6xx0.1)/(10)=0.046mol` This means that a minimum of `0.046mol` or `0.046xx1000=46` m mol are required coagulating `1L` of solution. Flocculation value of `AB` for `As_(2)S_(3)sol=46` |
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