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In a common-base connection, a certain transistor has an emitter current of 10mA and collector current of 9.8 mA. Calculate the value of the base current. |
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Answer» DATA : IE = 10 mA, IC = 9.8 mA IE = IB + IC Therefore, the base current, IB = IE – IC = 10 – 9.8 = 0.2 mA |
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