1.

In a common – base mode of a transistor, the collector current is 5.488 mA for an emitter current of 5.60 A. The value of the base current amplification factor (β) will be- (a) 49 (b) 50 (c) 51(d) 48.

Answer»

(a) 49

β = \(\frac{I_C}{I_B}\)\(\frac{5.488}{0.112}\) = 49.



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