In a common emitter amplifier, using output reisistance of `5000` ohm and input resistance fo `2000`ohm, if the peak value of input signal voltage is `10 m V` and `beta=50`, then the peak value of output voltage isA. `5xx10^(-6)` voltB. `2.5xx10^(-4)`C. `1.25` voltD. `125` volt

In a common emitter amplifier, using output reisistance of `5000` ohm

1.	In a common emitter amplifier, using output reisistance of `5000` ohm and input resistance fo `2000`ohm, if the peak value of input signal voltage is `10 m V` and `beta=50`, then the peak value of output voltage isA. `5xx10^(-6)` voltB. `2.5xx10^(-4)`C. `1.25` voltD. `125` volt
Answer» Correct Answer - B In common emitter mode, the transistor is current amplifier `DeltaI_(B)=(10xx10^(-3))/2000=5xx10^(-6) A` Again, `beta=(DeltaI_(C))/(DeltaI_(B))` or `DeltaI_(C)=betaxxDeltaI_(B)` `=50xx5xx10^(-6)A =250xx10^(-6)A` `=2.5xx10^(-4) A` Peak value of output voltage `=2.5xx10^(-4)xx5000` volt=`1.25` volt

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In a common emitter amplifier, using output reisistance of `5000` ohm and input resistance fo `2000`ohm, if the peak value of input signal voltage is `10 m V` and `beta=50`, then the peak value of output voltage isA. `5xx10^(-6)` voltB. `2.5xx10^(-4)`C. `1.25` voltD. `125` volt

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