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In a common emitter (CE) amplifier having a voltage gain G, the transistor used has tranconductance 0.02 mho and current gain 20, the voltage gain will be:A. ` 5/4 G`B. `2/3G`C. 1.5 GD. `1/3 G` |
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Answer» Correct Answer - B Voltage gain, `A_(V)=g_(m)xxR_(L)` (in magnitude) or `A_(V)propg_(m)` `:. A_(V_(2))/A_(V_(1))=g_(m_(2))/(g_(m_(1))) or A_(V_(2))/G=0.02/0.03=2/3 or A_(V_(2))=(2G)/3` |
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