In a compound, C, H and N are present in the ratio 9 : 1: 3.5 by weight. If the molecular weight. If the molecular weight of the compound is 108. Molecular formula of the compound is :

In a compound, C, H and N are present in the ratio 9 : 1: 3.5 by weigh

1.	In a compound, C, H and N are present in the ratio 9 : 1: 3.5 by weight. If the molecular weight. If the molecular weight of the compound is 108. Molecular formula of the compound is :
Answer» `C_(2)H_(6)N_(2)` `C_(3)H_(4)N` `C_(6)H_(8)N_(2)` `C_(9)H_(12)N_(3)` Solution :Percentage `C=(9)/(13.5)xx100=66.6` `H=(1)/(13.5)xx100=7.4` `N=(3.5)/(13.5)xx100=26.0` Atomic ration `C=underset(=5.5)((66.6)/(12)),H=underset(=7.4)((7.4)/(1)),N=underset(=1.86)((26.0)/(14))` Simplest ratio `C = 3,H=4,N=1` Empirical formula `= C_(3)H_(4)N` Empirical formula MASS `= 36 + 4 + 14 = 54` `n=("Molecular mass")/("Empirical formula mass")` `=(108)/(54)=2` Molecular formula `= C_(6)H_(8)N_(2)`.