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In a compound microscope, the focal lengths of two lenses are `1.5 cm` and `6.25 cm` an object is placed at `2 cm` form objective and the final image is formed at `25 cm` from eye lens. The distance between the two lenses isA. `6.00cm`B. `7.75cm`C. `9.25cm`D. `11.00cm` |
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Answer» Correct Answer - D `v_(0) = (f_(0)u_(0))/(u_(0)-f_(0)) = (1.5xx2)/(2-1.5) = 6cm` `u_(e) = (f_(e)D)/(f_(e)+D) =(6.25 xx 25)/(25+6.25) = 5cm` `L = v_(0)+u_(e) = 6+5 = 11 cm` (Distance between the lens is the length of tube) |
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