InterviewSolution
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InterviewSolution
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In a CPS (close packed structure) of mixed oxides, it is found that lattice has `O^(2-)` (oxide ions), and one half of octahedral voids are occupied by trivalent cations `(A^(3+))` and one-eight of tetrahedral voids are occupied by divalent cation `(B^(2+))`. Derive formula of the mixed oxide. |
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Answer» Number of octahedral voids ion in lattice = 1 Hence, Number of trivalent cations `(A^(3+)) = 1 xx (1)/(2) = (1)/(2)` Number of tetrahedral voids per ion in lattice = 2 Hence, Number of divalent cations `(B^(2+)) = 2 xx (1)/(8) = (1)/(4)` Thus, formula is `A_(1//2)O " or " A_(2)BO_(4)` |
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