1.

In a crystal of an ionic compound, the ions B form the close packed lattice and the ions A occupy all the tetrahedral voids. The formula of the compound is

Answer»

`AB_(2)`
`A_(2)B`
AB
`AB_(3)`

SOLUTION :The number of tetrahedral voids is two PER ATOM of the crystal in a close packed structure. Since tetrahedral voids are occupied by A ions, there are two A ions per B ion inthe crystal.The formula of the compound is `A_(2)B`.


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