InterviewSolution
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InterviewSolution
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In a cubic,`A` atoms are present on alternative corners, `B` atoms are present on alternate faces, and `C` atoms are present on alternalte edges and body centred of the cube. The simplest formula of the compound isA. `A_(2)BC_(4)`B. `AB_(2)C_(4)`C. `ABC_(4)`D. `ABC_(2)` |
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Answer» Correct Answer - B Number of `A` atoms at alternate corners `= 4` corner `xx (1)/(8)` per corner share `= (1)/(2)` Number of `B` atoms at alternate face `= 2` faces `xx (1)/(2)` per face center share `= 1` Number of `C` atoms at alternate edges and at body centre `=` (`4` edges `xx (1)/(4)` per edge centre share) `+ 1` atom at body centre `= 1 + 1 = 2` Thus, formula `A_((1)/(2))B_(1)C_(2)` Simplifying, `AB_(2)C_(4)`. |
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