1.

In a cyclic process shown in the figure an ideal gas is adiabatically taken from B to A, the work done on the gas during the processB toAis 30 J, when the gas is taken fromA to Bthe heat absorbed by the gas is 20J. What is The change in internal energy of the gas in the process A to B.

Answer»

SOLUTION :
`W_(BA) = -30J, Q_(BA)=0`
`:.DeltaU_(BA)= -W_(BA)=30J`
In a cyclic PROCESS `DeltaU=0`
Now, `DeltaU_(AB)= -DeltaU_(BA)= -30J`


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