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In a cyclic process shown in the figure on ideal gas is adiabatically taken from B to A, the work done on the gas during the process B rarr A is 30J, when the gas is taken from A rarr Bthe heat absorbed by the gas is 20J. What is the change in internal ebergy of the gas in the process A rarr B. |
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Answer» SOLUTION :`W_(BA)= -30J,Q_(BA) = 0` `:. DELTA U_(BA) = -W_(BA) = 30J` In a cyclic process `DeltaU=0` Now, `Delta U_(AB) = -Delta U_(BA) = -30J`
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