1.

In a cyclic process shown in the figure on ideal gas is adiabatically taken from B to A, the work done on the gas during the process B rarr A is 30J, when the gas is taken from A rarr Bthe heat absorbed by the gas is 20J. What is the change in internal ebergy of the gas in the process A rarr B.

Answer»

SOLUTION :`W_(BA)= -30J,Q_(BA) = 0`
`:. DELTA U_(BA) = -W_(BA) = 30J`
In a cyclic process `DeltaU=0`
Now, `Delta U_(AB) = -Delta U_(BA) = -30J`


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