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In a cyclic quadrilateral ABCD if AB||CD and B = 70° , find the remaining angles. |
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Answer» A cyclic quadrilateral ABCD with AB||CD and B = 70°. ∠B + ∠C = 180° (Co-interior angle) 70° + ∠C = 180° ∠C = 110° And, => ∠B + ∠D = 180° (Opposite angles of Cyclic quadrilateral) 70° + ∠D = 180° ∠D = 110° Again, ∠A + ∠C = 180° (Opposite angles of cyclic quadrilateral) ∠A + 110° = 180° ∠A = 70° Answer: ∠A = 70° , ∠C = 110° and ∠D = 110° |
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