1.

In a Δ ABC, AB = AC andlA.= 50° find ∠B and ∠C.

Answer»

∠A+ ∠B + ∠C = 180° 

(Sum of the angles of a triangle is 180° ) 

50° +∠B + ∠B = 180° 

∠B = ∠C Base angles of an isosceles triangle 

50 + 2∠B= 180° 

2∠B = 180 – 50 

2∠B = 130° 

∠B = \(\frac{130^o}{2}\)

∠B = 65° 

∠B = ∠C = 65°


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