1.

In a ΔABC, if ∣∣∣∣1ab1ca1bc∣∣∣∣=0, then sin2A+sin2B+sin2C=

Answer»

In a ΔABC, if ∣∣
∣
∣
1ab1ca1bc∣∣
∣
∣
=0
, then sin2A+sin2B+sin2C=



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