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In a ` Delta ABC, angle C = 3 angle B = 2 (angle A + angle B)`, then ` angle B ` = ?A. `20^(@)`B. `40 ^(@)`C. ` 60 ^(@)`D. `80^(@)` |
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Answer» Correct Answer - B Let `C = 3B = 2(A+B) = x ^(@)` Then, `C = x ^(@), B = ((x)/(3))^(@) and (A + B) = ((x)/(2)) ^(@)`. `(A + B) +C = 180^(@) rArr (x)/(2) + x = 180 rArr 3x = 360 rArr x = 120 `. ` therefore angle B = ((120)/(3))^(@) = 40 ^(@)` |
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